What is the domain of f(x)= 1/(sqrt(t+7)) ?

The domain of f(x)= 1/(sqrt(t+7)) is t>-7

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domain of f(x)= 1/(sqrt(t+7))

domain

f (x) = \frac{1}{t + 7}

t > - 7

Interval Notation

(- 7, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 7

Find undefined (singularity) points:

t = - 7

Combine real regions and undefined points for final function domain

t > - 7

f (x) = x^{4} - 16

6^{x} + 2

f (x) = \frac{2 x}{3 x - 4}

X^{2} - 1

\frac{4 x}{x ^{2} - 1}

What is the domain of f(x)= 1/(sqrt(t+7)) ?
The domain of f(x)= 1/(sqrt(t+7)) is t>-7