What is the domain of f(x)=sqrt(x^4-16) ?

The domain of f(x)=sqrt(x^4-16) is x = 2

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domain of f(x)=sqrt(x^4-16)

domain

f (x) = x^{4} - 16

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

6^{x} + 2

f (x) = \frac{2 x}{3 x - 4}

X^{2} - 1

\frac{4 x}{x ^{2} - 1}

f (x) = x + 25

What is the domain of f(x)=sqrt(x^4-16) ?
The domain of f(x)=sqrt(x^4-16) is x<=-2\lor x>= 2