What is the domain of y= 1/(ln(x)) ?

The domain of y= 1/(ln(x)) is 0 1

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domain of y= 1/(ln(x))

domain

y = \frac{1}{ln ( x )}

0 < x < 1 or x > 1

Interval Notation

(0, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x > 0

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 < x < 1 or x > 1

f (x) = x + 64

f (x) = \frac{10 x ^{2} + x}{x ^{2} + 8}

f (x) = \frac{( n - 1 ) ( - 1 ) ^{n + 1}}{2 n + 3}

f (x) = cosh (t^{3} - 8)

f (x) = \frac{14 - 5 x}{3 x + 4}

What is the domain of y= 1/(ln(x)) ?
The domain of y= 1/(ln(x)) is 0<x<1\lor x>1