What is the domain of f(x)=(3x)/(x^2+2x-3) ?

The domain of f(x)=(3x)/(x^2+2x-3) is x 1

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domain of f(x)=(3x)/(x^2+2x-3)

domain

f (x) = \frac{3 x}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = \frac{x - 1}{x ( x ^{2} - 2 x - 15 )}

\frac{x ^{2} + x - 6}{( x + 8 ) ( x ^{2} - x - 2 )}

3 x^{4} + 4 x^{3} - 12 x^{2}

\frac{( x + 1 )}{( x ^{2} - 4 x + 3 )}

f (x) = ln (9 - 3 t)

What is the domain of f(x)=(3x)/(x^2+2x-3) ?
The domain of f(x)=(3x)/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1