What is the domain of f(x)=(sqrt(4x-3))/(x^2-4) ?

The domain of f(x)=(sqrt(4x-3))/(x^2-4) is 3/4 2

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domain of f(x)=(sqrt(4x-3))/(x^2-4)

domain

f (x) = \frac{4 x - 3}{x ^{2} - 4}

\frac{3}{4} \leq x < 2 or x > 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{4}

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

\frac{3}{4} \leq x < 2 or x > 2

f (x) = 3 - x - \frac{2}{x}

f (x) = - 1 + lo g_{3} (x + 3)

f (x) = - 3 (\frac{1}{3})^{x + 2} - 1

f (x) = 3 x^{2} - x

y = 4 x - 16

What is the domain of f(x)=(sqrt(4x-3))/(x^2-4) ?
The domain of f(x)=(sqrt(4x-3))/(x^2-4) is 3/4 <= x<2\lor x>2