What is the domain of f(x)=\sqrt[3]{x^2}-x ?

The domain of f(x)=\sqrt[3]{x^2}-x is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x^2}-x

domain

f (x) = 3 x^{2} - x

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = 4 x - 16

g (x) = \frac{x}{x ^{2} + 9}

arctan (\frac{1 + x}{1 - x})

\frac{1}{2.3 x - 7.8 x ^{2}}

f (x) = \frac{( x - 8 ) ( x - 2 )}{x - 7}

What is the domain of f(x)=\sqrt[3]{x^2}-x ?
The domain of f(x)=\sqrt[3]{x^2}-x is -infinity <x<infinity