What is the domain of g(x)= x/(x^2+9) ?

The domain of g(x)= x/(x^2+9) is -infinity <x<infinity

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domain of g(x)= x/(x^2+9)

domain

g (x) = \frac{x}{x ^{2} + 9}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

arctan (\frac{1 + x}{1 - x})

\frac{1}{2.3 x - 7.8 x ^{2}}

f (x) = \frac{( x - 8 ) ( x - 2 )}{x - 7}

g (x) = \frac{2}{x - 2}

\frac{x - 7}{8}

What is the domain of g(x)= x/(x^2+9) ?
The domain of g(x)= x/(x^2+9) is -infinity <x<infinity