What is the domain of f(x)=(-6x+12)/(3x+4) ?

The domain of f(x)=(-6x+12)/(3x+4) is x -4/3

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domain of f(x)=(-6x+12)/(3x+4)

domain

f (x) = \frac{- 6 x + 12}{3 x + 4}

x < - \frac{4}{3} or x > - \frac{4}{3}

Interval Notation

(- \infty, - \frac{4}{3}) \cup (- \frac{4}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{4}{3}

The function domain

x < - \frac{4}{3} or x > - \frac{4}{3}

f (x) = x^{4} e^{- x}

\frac{∣ 5 - x ∣}{x ^{2} - 12 x + 35}

\frac{3 x - 1}{2}

f (x) = 19 - 19 x

f (x) = \frac{2 + x - 5}{x ^{2} - 64}

What is the domain of f(x)=(-6x+12)/(3x+4) ?
The domain of f(x)=(-6x+12)/(3x+4) is x<-4/3 \lor x>-4/3