What is the domain of f(x)=(2+sqrt(x-5))/(x^2-64) ?

The domain of f(x)=(2+sqrt(x-5))/(x^2-64) is 5 8

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domain of f(x)=(2+sqrt(x-5))/(x^2-64)

domain

f (x) = \frac{2 + x - 5}{x ^{2} - 64}

5 \leq x < 8 or x > 8

Interval Notation

[5, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

Find undefined (singularity) points:

x = 8, x = - 8

Combine real regions and undefined points for final function domain

5 \leq x < 8 or x > 8

f (x) = 3 + 5 + 9 x

- ln (7 - x) + 3

5

4

f (x) = \frac{1 - 2 x}{x}

What is the domain of f(x)=(2+sqrt(x-5))/(x^2-64) ?
The domain of f(x)=(2+sqrt(x-5))/(x^2-64) is 5<= x<8\lor x>8