What is the domain of f(x)= 1/(x^2-4x) ?

The domain of f(x)= 1/(x^2-4x) is x 4

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domain of f(x)= 1/(x^2-4x)

domain

f (x) = \frac{1}{x ^{2} - 4 x}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 0

The function domain

x < 0 or 0 < x < 4 or x > 4

- 4 x + 9

f (x) = x^{3} + 3 x^{2} - 25 x - 75

\frac{x ^{2} - 12 x + 32}{x ^{2} - 6 x + 8}

f (x) = \frac{( x - 3 )}{( x + 5 )}

f (x) = 2 - 3 x^{2} + 7 x, - 4 \leq x \leq 8

What is the domain of f(x)= 1/(x^2-4x) ?
The domain of f(x)= 1/(x^2-4x) is x<0\lor 0<x<4\lor x>4