What is the domain of f(x)=(12)/(6x^2-7x-20) ?

The domain of f(x)=(12)/(6x^2-7x-20) is x 5/2

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domain of f(x)=(12)/(6x^2-7x-20)

domain

f (x) = \frac{12}{6 x ^{2} - 7 x - 20}

x < - \frac{4}{3} or - \frac{4}{3} < x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

(- \infty, - \frac{4}{3}) \cup (- \frac{4}{3}, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{2}, x = - \frac{4}{3}

The function domain

x < - \frac{4}{3} or - \frac{4}{3} < x < \frac{5}{2} or x > \frac{5}{2}

y = lo g_{10} (5 - 6 x)

f (x) = \frac{x - 1}{x + 7}

- arcsin (t)

f (x) = 4 x + 36

\frac{4}{x - 7}

What is the domain of f(x)=(12)/(6x^2-7x-20) ?
The domain of f(x)=(12)/(6x^2-7x-20) is x<-4/3 \lor-4/3 <x< 5/2 \lor x> 5/2