What is the domain of log_{10}(2((sqrt(x-1)))+1) ?

The domain of log_{10}(2((sqrt(x-1)))+1) is x>= 1

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domain of log_{10}(2((sqrt(x-1)))+1)

domain

lo g_{10} (2 ((x - 1)) + 1)

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find positive values for logs:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{1}{4 x + 1}

4 x^{2} + 8 x + 3

f (x) = \frac{arctan ( x )}{x ^{2} - 1}

f (x) = 4 x - 5 y + 7 = 0

f (x) = \frac{x - 4}{x - 5}

What is the domain of log_{10}(2((sqrt(x-1)))+1) ?
The domain of log_{10}(2((sqrt(x-1)))+1) is x>= 1