What is the domain of f(x)=(x-3)/(x^2+1) ?

The domain of f(x)=(x-3)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(x-3)/(x^2+1)

domain

f (x) = \frac{x - 3}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x - 5}{x ^{2}}

\frac{1}{36 - x ^{2}}

f (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

\frac{1}{t + 2} + t + 1

y = e

What is the domain of f(x)=(x-3)/(x^2+1) ?
The domain of f(x)=(x-3)/(x^2+1) is -infinity <x<infinity