What is the domain of f(x)= 1/(sqrt(2t-3)) ?

The domain of f(x)= 1/(sqrt(2t-3)) is t> 3/2

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domain of f(x)= 1/(sqrt(2t-3))

domain

f (x) = \frac{1}{2 t - 3}

t > \frac{3}{2}

Interval Notation

(\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

t \geq \frac{3}{2}

Find undefined (singularity) points:

t = \frac{3}{2}

Combine real regions and undefined points for final function domain

t > \frac{3}{2}

f (x) = - lo g_{4} (x)

f (x) = \frac{( x ^{2} + 3 ) x - 5}{x - 5}

+ 38 (e^{t} - 1)

8 x - 9

\frac{6 ( x + 4 )}{( x ^{2} - 16 )}

What is the domain of f(x)= 1/(sqrt(2t-3)) ?
The domain of f(x)= 1/(sqrt(2t-3)) is t> 3/2