What is the domain of f(x)=ln(x^2+x-2) ?

The domain of f(x)=ln(x^2+x-2) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=ln(x^2+x-2)

domain

f (x) = ln (x^{2} + x - 2)

x < - 2 or x > 1

Interval Notation

(- \infty, - 2) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 2 or x > 1

The function domain

x < - 2 or x > 1

f (x) = \frac{x - 1}{x}

x^{3} + 7

f (x) = \frac{x}{x ^{2} + 12 x + 32}

y = \frac{x - 2}{x + 2}

f (x) = arcsin (\frac{1 - x ^{2}}{1 + x ^{2}})

What is the domain of f(x)=ln(x^2+x-2) ?
The domain of f(x)=ln(x^2+x-2) is x<-2\lor x>1