What is the domain of f(x)=2^{1/x} ?

The domain of f(x)=2^{1/x} is x 0

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domain of f(x)=2^{1/x}

domain

f (x) = 2^{\frac{1}{x}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = x^{3} + 6 x^{2} + 8 x

y = - \frac{3}{x}

ln (arcsin (x))

f (x) = - 1 + 2 - x^{2}

cos (arctan (1 - x^{2}))