What is the domain of f(x)=-1+sqrt(2-x^2) ?

The domain of f(x)=-1+sqrt(2-x^2) is -sqrt(2)<= x<= sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=-1+sqrt(2-x^2)

domain

f (x) = - 1 + 2 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

cos (arctan (1 - x^{2}))

f (x) = \frac{x ^{2} - 9 x - 36}{x + 16}

1 + ln (x^{3} - 8)

f (x) = \frac{1}{1 - cos ^{2} ( x - \frac{3}{2} )}

\frac{x + 8}{3}

What is the domain of f(x)=-1+sqrt(2-x^2) ?
The domain of f(x)=-1+sqrt(2-x^2) is -sqrt(2)<= x<= sqrt(2)