What is the domain of y=ln(3x^2-2x-1) ?

The domain of y=ln(3x^2-2x-1) is x 1

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domain of y=ln(3x^2-2x-1)

domain

y = ln (3 x^{2} - 2 x - 1)

x < - \frac{1}{3} or x > 1

Interval Notation

(- \infty, - \frac{1}{3}) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - \frac{1}{3} or x > 1

The function domain

x < - \frac{1}{3} or x > 1

2 (4 x - 9) + 5

f (x) = \frac{1}{2} ln (10 x + 5)

\frac{x + 5}{x ^{2} - 3 x + 5}

f (x) = 4 - 5^{2 - x}

f (x) = x^{2} - 6 x + 5

What is the domain of y=ln(3x^2-2x-1) ?
The domain of y=ln(3x^2-2x-1) is x<-1/3 \lor x>1