What is the domain of f(x)=sqrt(x^2-6x+5) ?

The domain of f(x)=sqrt(x^2-6x+5) is x = 5

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domain of f(x)=sqrt(x^2-6x+5)

domain

f (x) = x^{2} - 6 x + 5

x \leq 1 or x \geq 5

Interval Notation

(- \infty, 1] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 5

The function domain

x \leq 1 or x \geq 5

f (x) = - 4.3

- 3 csc (\frac{π}{2} t) - 3

f (x) = 4 sin^{2} (x), - π \leq x \leq π

f (t) = \frac{5 t ^{2} - 64}{3 t + 17}

- 2 x - 5

What is the domain of f(x)=sqrt(x^2-6x+5) ?
The domain of f(x)=sqrt(x^2-6x+5) is x<= 1\lor x>= 5