What is the domain of f(x)=(sqrt(2-x))/(x^2-4x+3) ?

The domain of f(x)=(sqrt(2-x))/(x^2-4x+3) is x<1\lor 1<x<= 2

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domain of f(x)=(sqrt(2-x))/(x^2-4x+3)

domain

f (x) = \frac{2 - x}{x ^{2} - 4 x + 3}

x < 1 or 1 < x \leq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq 2

Find undefined (singularity) points:

x = 3, x = 1

Combine real regions and undefined points for final function domain

x < 1 or 1 < x \leq 2

f (x) = - 5.4

f (x) = 4^{l o g_{2} (16 x) + 1} = 1

f (x) = \frac{( x ^{2} + 1 ) ( x + 1 )}{x - 1}

f (x) = 3 x^{2} + 1

\frac{- 2}{x - 2}

What is the domain of f(x)=(sqrt(2-x))/(x^2-4x+3) ?
The domain of f(x)=(sqrt(2-x))/(x^2-4x+3) is x<1\lor 1<x<= 2