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Popular >

extreme f(x)=x^3-3x^2+3x

Solution

extreme points

f (x) = x^{3} - 3 x^{2} + 3 x

Solution

Saddle (1, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 3

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{3} - 3 x^{2} + 3 x : 1

Saddle (1, 1)

Popular Examples

extreme f(x,y)=x^2+xy+3x+2y+5 extreme points

f (x, y) = x^{2} + x y + 3 x + 2 y + 5

extreme f(x)=xy extreme points

f (x) = x y

extreme f(x,y)=ln(xy-6)extreme points

f (x, y) = ln (x y - 6)

extreme f(x,y)=xy+1/x+1/y extreme points

f (x, y) = x y + \frac{1}{x} + \frac{1}{y}

extreme f(x)=2x^3-3x^2 extreme points

f (x) = 2 x^{3} - 3 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-3x^2+3x ?
The extreme f(x)=x^3-3x^2+3x is Saddle(1,1)