What is the extreme f(x)=2x^3+3x^2-120x ?

The extreme f(x)=2x^3+3x^2-120x is Maximum(-5,425),Minimum(4,-304)

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extreme f(x)=2x^3+3x^2-120x

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 120 x

Maximum (- 5, 425), Minimum (4, - 304)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 120

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 5

into

2 x^{3} + 3 x^{2} - 120 x : 425

Maximum (- 5, 425)

Plug

x = 4

into

2 x^{3} + 3 x^{2} - 120 x : - 304

Minimum (4, - 304)

Maximum (- 5, 425), Minimum (4, - 304)

f (x) = - 4 x^{3} + 3 x^{2} + 18 x

\frac{e ^{x}}{x}

f (x, y) = 2 x^{2} - 8 x + y^{2} + 16 y + 100

f (x, y) = \frac{1}{25 - x ^{2} - y ^{2}}

f (x) = 1 - x^{2}

What is the extreme f(x)=2x^3+3x^2-120x ?
The extreme f(x)=2x^3+3x^2-120x is Maximum(-5,425),Minimum(4,-304)