What is the extreme f(x,y)=3x^2-4y^2 ?

The extreme f(x,y)=3x^2-4y^2 is Saddle(0,0)

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extreme f(x,y)=3x^2-4y^2

extreme points

f (x, y) = 3 x^{2} - 4 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = - 48

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

\frac{x ^{3}}{x ^{2} - 1}

f (x, y) = x^{3} - 12 x y + 8 y^{3}

f (x, y) = x^{2} + x y + y^{2} + y

f (x) = x e^{(\frac{x}{2})}

f (x) = x^{5} ln (x)

What is the extreme f(x,y)=3x^2-4y^2 ?
The extreme f(x,y)=3x^2-4y^2 is Saddle(0,0)