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Popular >

extreme y=e^{rx}

Solution

extreme points

y = e^{r x}

Solution

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial r ^{2}} = e^{r x} r^{2}

D (r, x) = - 2 e^{2 r x} r x - e^{2 r x}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

Popular Examples

extreme (-2x^2+5x-1)/(2x-1)extreme points

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

extreme f(x)=x^3-6x^2+9x+2 extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 2

extreme f(x)=-x^4+6x^2-4 extreme points

f (x) = - x^{4} + 6 x^{2} - 4

extreme f(x)=3x^4-4x^3+1 extreme points

f (x) = 3 x^{4} - 4 x^{3} + 1

extreme f(x,y)=x^3+3xy^2-15x-12y extreme points

f (x, y) = x^{3} + 3 x y^{2} - 15 x - 12 y

Frequently Asked Questions (FAQ)

What is the extreme y=e^{rx} ?
The extreme y=e^{rx} is Saddle(0,0)