What is the extreme f(x)=6x^5-40x^3+14 ?

The extreme f(x)=6x^5-40x^3+14 is Maximum(-2,142),Saddle(0,14),Minimum(2,-114)

Popular >

extreme f(x)=6x^5-40x^3+14

extreme points

f (x) = 6 x^{5} - 40 x^{3} + 14

Maximum (- 2, 142), Saddle (0, 14), Minimum (2, - 114)

Solution steps

f^{'} (x) = 30 x^{4} - 120 x^{2}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

6 x^{5} - 40 x^{3} + 14 : 142

Maximum (- 2, 142)

Plug

x = 0

into

6 x^{5} - 40 x^{3} + 14 : 14

Saddle (0, 14)

Plug

x = 2

into

6 x^{5} - 40 x^{3} + 14 : - 114

Minimum (2, - 114)

Maximum (- 2, 142), Saddle (0, 14), Minimum (2, - 114)

f (x) = - x^{4} + 4 x^{3} + 20

f (x) = 3 x + 4 y

f (x) = - 2 x^{2} + 8 x - 5

f (x) = \frac{x ^{2}}{x ^{2} + 1}

f (x, y) = 7 + x + 4 y - x^{2} - 4 y^{2}

What is the extreme f(x)=6x^5-40x^3+14 ?
The extreme f(x)=6x^5-40x^3+14 is Maximum(-2,142),Saddle(0,14),Minimum(2,-114)