What is the extreme f(x)=-(x^2)/2+5/2 x ?

The extreme f(x)=-(x^2)/2+5/2 x is Maximum(5/2 , 25/8)

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extreme f(x)=-(x^2)/2+5/2 x

extreme points

f (x) = - \frac{x ^{2}}{2} + \frac{5}{2} x

Maximum (\frac{5}{2}, \frac{25}{8})

Solution steps

f^{'} (x) = - x + \frac{5}{2}

Find intervals:

Increasing

: - \infty < x < \frac{5}{2},

Decreasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

- \frac{x ^{2}}{2} + \frac{5}{2} x : \frac{25}{8}

Maximum (\frac{5}{2}, \frac{25}{8})

f (x) = ln (9 - x^{2} - 9 y^{2})

x^{4} + y^{4} - 4 x y + 5

f (x, y) = y x^{2} - 2 x^{2} - y^{2}

f (x, y) = x y e^{- x^{2} - y^{2}}

f (x) = x^{2} + 6 x + 9

What is the extreme f(x)=-(x^2)/2+5/2 x ?
The extreme f(x)=-(x^2)/2+5/2 x is Maximum(5/2 , 25/8)