What is the extreme f(x)=2x^3-6x+3 ?

The extreme f(x)=2x^3-6x+3 is Maximum(-1,7),Minimum(1,-1)

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extreme f(x)=2x^3-6x+3

extreme points

f (x) = 2 x^{3} - 6 x + 3

Maximum (- 1, 7), Minimum (1, - 1)

Solution steps

f^{'} (x) = 6 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x + 3 : 7

Maximum (- 1, 7)

Plug

x = 1

into

2 x^{3} - 6 x + 3 : - 1

Minimum (1, - 1)

Maximum (- 1, 7), Minimum (1, - 1)

3 x - x^{3}

f (x, y) = y ln (- y + x)

f (x) = - 2 x^{3} - 9 x^{2} + 24 x + 40

f (x, y) = x^{2} y + y^{3} - 48 y

f (x, y) = (5 x + 3 y + 10) (4 y + 2)

What is the extreme f(x)=2x^3-6x+3 ?
The extreme f(x)=2x^3-6x+3 is Maximum(-1,7),Minimum(1,-1)