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Popular >

extreme f(x)=sqrt(x^2+36)

Solution

extreme points

f (x) = x^{2} + 36

Solution

Minimum (0, 6)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} + 36}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 36 : 6

Minimum (0, 6)

Popular Examples

extreme y=3x^2+12x extreme points

y = 3 x^{2} + 12 x

extreme f(x)=-2x^3+12x^2+18 extreme points

f (x) = - 2 x^{3} + 12 x^{2} + 18

extreme f(x)=-x^3+3x^2 extreme points

f (x) = - x^{3} + 3 x^{2}

extreme f(x,y)=3-x^2-y^2 extreme points

f (x, y) = 3 - x^{2} - y^{2}

extreme f(x,y)=2xy-5x^2-2y^2+18y-8 extreme points

f (x, y) = 2 x y - 5 x^{2} - 2 y^{2} + 18 y - 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2+36) ?
The extreme f(x)=sqrt(x^2+36) is Minimum(0,6)