What is the extreme f(x)=2x^3-3x^2-36x+24 ?

The extreme f(x)=2x^3-3x^2-36x+24 is Maximum(-2,68),Minimum(3,-57)

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extreme f(x)=2x^3-3x^2-36x+24

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 36 x + 24

Maximum (- 2, 68), Minimum (3, - 57)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

2 x^{3} - 3 x^{2} - 36 x + 24 : 68

Maximum (- 2, 68)

Plug

x = 3

into

2 x^{3} - 3 x^{2} - 36 x + 24 : - 57

Minimum (3, - 57)

Maximum (- 2, 68), Minimum (3, - 57)

f (x) = x^{3} - 6 x^{2} + 9 x + 15

f (x, y) = 2 x + 2 x y + y

x^{2} y - x^{2} - 2 y^{2}

f (x) = 3 - 4 sin (3 x)

f (x, y) = ln ∣ 4 - x - y ∣

What is the extreme f(x)=2x^3-3x^2-36x+24 ?
The extreme f(x)=2x^3-3x^2-36x+24 is Maximum(-2,68),Minimum(3,-57)