What is the extreme f(x)=-x^4-8x^3-18x^2+6 ?

The extreme f(x)=-x^4-8x^3-18x^2+6 is Saddle(-3,-21),Maximum(0,6)

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extreme f(x)=-x^4-8x^3-18x^2+6

extreme points

f (x) = - x^{4} - 8 x^{3} - 18 x^{2} + 6

Saddle (- 3, - 21), Maximum (0, 6)

Solution steps

f^{'} (x) = - 4 x^{3} - 24 x^{2} - 36 x

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 3

into

- x^{4} - 8 x^{3} - 18 x^{2} + 6 : - 21

Saddle (- 3, - 21)

Plug

x = 0

into

- x^{4} - 8 x^{3} - 18 x^{2} + 6 : 6

Maximum (0, 6)

Saddle (- 3, - 21), Maximum (0, 6)

f (x) = x^{3} - 6 x^{2} + 9 x - 2

f (x) = \frac{x}{x ^{2} - x + 9}

f (x, y) = ∣ x ∣ + y^{2} - 1

E, E = I R

f (x) = x^{2} - 4 x - 5

What is the extreme f(x)=-x^4-8x^3-18x^2+6 ?
The extreme f(x)=-x^4-8x^3-18x^2+6 is Saddle(-3,-21),Maximum(0,6)