What is the extreme f(x)=9x^{2/3}+3x-6 ?

The extreme f(x)=9x^{2/3}+3x-6 is Minimum(-8,6),Maximum(0,-6)

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extreme f(x)=9x^{2/3}+3x-6

extreme points

f (x) = 9 x^{\frac{2}{3}} + 3 x - 6

Minimum (- 8, 6), Maximum (0, - 6)

Solution steps

f^{'} (x) = \frac{6}{x ^{\frac{1}{3}}} + 3

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{8},

Increasing

: - \frac{1}{8} < x < \infty

Plug

x = - 8

into

9 x^{\frac{2}{3}} + 3 x - 6 : 6

Minimum (- 8, 6)

Plug

x = 0

into

9 x^{\frac{2}{3}} + 3 x - 6 : - 6

Maximum (0, - 6)

Minimum (- 8, 6), Maximum (0, - 6)

f (x, y) = (x^{2} + y^{2})

f (x) = \frac{x ^{2} - 2 x + 2}{x - 1}

f (x) = 2 x^{3} - 9 x^{2} + 27

f (x, y) = x^{2} - x^{2} y^{2} + y^{2}

f (x, y) = x^{2} y + 4 x y - 2 y^{2} - 3

What is the extreme f(x)=9x^{2/3}+3x-6 ?
The extreme f(x)=9x^{2/3}+3x-6 is Minimum(-8,6),Maximum(0,-6)