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Popular >

extreme f(x)=x^2-2x-8

Solution

extreme points

f (x) = x^{2} - 2 x - 8

Solution

Minimum (1, - 9)

Solution steps

f^{'} (x) = 2 x - 2

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{2} - 2 x - 8 : - 9

Minimum (1, - 9)

Popular Examples

extreme f(x)=(-8)/(x^2-4)extreme points

f (x) = \frac{- 8}{x ^{2} - 4}

extreme f(x)=(x^2-x-2)/(x^2-6x+9)extreme points

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 6 x + 9}

extreme f(x,y)=xy+8/x+8/y extreme points

f (x, y) = x y + \frac{8}{x} + \frac{8}{y}

extreme f(x,y)=xy-7xy+200x extreme points

f (x, y) = x y - 7 x y + 200 x

extreme f(x,y)=xy-5x-5y-x^2-y^2 extreme points

f (x, y) = x y - 5 x - 5 y - x^{2} - y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-2x-8 ?
The extreme f(x)=x^2-2x-8 is Minimum(1,-9)