What is the extreme g(x,y)=x^3-3xy^2+y^3 ?

The extreme g(x,y)=x^3-3xy^2+y^3 is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme g(x,y)=x^3-3xy^2+y^3

extreme points

g (x, y) = x^{3} - 3 x y^{2} + y^{3}

None

Solution steps

Find the critical points:

None

x^{3} - 3 x y^{2} + y^{3}

has no critical points, therefore there are no extreme points

None

f (x) = x^{2} + x

f (x) = \frac{x}{x ^{2} - x + 4}, 0 \leq x \leq 6

f (x) = x^{3} - 6 x^{2} + 11

f (x, y) = 6 x - 4 y - x^{2} - 2 y^{2}

f (x, y) = 10 x^{2} y - 5 x^{2} - 4 y^{2} - x^{4} - 2 y^{4}

What is the extreme g(x,y)=x^3-3xy^2+y^3 ?
The extreme g(x,y)=x^3-3xy^2+y^3 is None