What is the extreme f(x)=2x^3-6x+4 ?

The extreme f(x)=2x^3-6x+4 is Maximum(-1,8),Minimum(1,0)

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extreme f(x)=2x^3-6x+4

extreme points

f (x) = 2 x^{3} - 6 x + 4

Maximum (- 1, 8), Minimum (1, 0)

Solution steps

f^{'} (x) = 6 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x + 4 : 8

Maximum (- 1, 8)

Plug

x = 1

into

2 x^{3} - 6 x + 4 : 0

Minimum (1, 0)

Maximum (- 1, 8), Minimum (1, 0)

f (x, y) = x^{2} y + y^{3} - 75 y

f (x, y) = e^{- x - y}

f (x, y) = x^{2} + y^{2} - 4

f (x, y) = 9 x^{2} + 2 y^{2} - 2 x y^{2}

f (x) = 2 x^{3} - 2 x^{2} - 16 x + 1

What is the extreme f(x)=2x^3-6x+4 ?
The extreme f(x)=2x^3-6x+4 is Maximum(-1,8),Minimum(1,0)