What is the extreme f(x)=2x^3-2x^2-16x+1 ?

The extreme f(x)=2x^3-2x^2-16x+1 is Maximum(-4/3 , 379/27),Minimum(2,-23)

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extreme f(x)=2x^3-2x^2-16x+1

extreme points

f (x) = 2 x^{3} - 2 x^{2} - 16 x + 1

Maximum (- \frac{4}{3}, \frac{379}{27}), Minimum (2, - 23)

Solution steps

f^{'} (x) = 6 x^{2} - 4 x - 16

Find intervals:

Increasing

: - \infty < x < - \frac{4}{3},

Decreasing

: - \frac{4}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{4}{3}

into

2 x^{3} - 2 x^{2} - 16 x + 1 : \frac{379}{27}

Maximum (- \frac{4}{3}, \frac{379}{27})

Plug

x = 2

into

2 x^{3} - 2 x^{2} - 16 x + 1 : - 23

Minimum (2, - 23)

Maximum (- \frac{4}{3}, \frac{379}{27}), Minimum (2, - 23)

f (x) = x + x^{2} - x^{3}

f (x) = e^{x + y}

f (x) = 6 x^{3} - 15 x^{2} + 12 x - 6

f (x) = 4 x^{3} - x^{2} - 4 x + 3

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 12

What is the extreme f(x)=2x^3-2x^2-16x+1 ?
The extreme f(x)=2x^3-2x^2-16x+1 is Maximum(-4/3 , 379/27),Minimum(2,-23)