What is the extreme f(x)=2x^3-3x^2-12x+12 ?

The extreme f(x)=2x^3-3x^2-12x+12 is Maximum(-1,19),Minimum(2,-8)

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extreme f(x)=2x^3-3x^2-12x+12

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 12

Maximum (- 1, 19), Minimum (2, - 8)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x + 12 : 19

Maximum (- 1, 19)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x + 12 : - 8

Minimum (2, - 8)

Maximum (- 1, 19), Minimum (2, - 8)

f (x, y) = 2 x^{3} - 6 x + 6 x y^{2}

f (x, y) = e^{x} ln (y)

f (x) = 3 x^{4} - 4 x^{3}, - 1 \leq x \leq 2

f (x) = x^{3} + 45 x^{2} + 87 x + 28

f (x, y) = x^{3} y + x y^{3} - 2 x y

What is the extreme f(x)=2x^3-3x^2-12x+12 ?
The extreme f(x)=2x^3-3x^2-12x+12 is Maximum(-1,19),Minimum(2,-8)