What is the extreme f(x,y)=e^xln(y) ?

The extreme f(x,y)=e^xln(y) is None

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extreme f(x,y)=e^xln(y)

extreme points

f (x, y) = e^{x} ln (y)

None

Solution steps

Find the critical points:

None

e^{x} ln (y)

has no critical points, therefore there are no extreme points

None

f (x) = 3 x^{4} - 4 x^{3}, - 1 \leq x \leq 2

f (x) = x^{3} + 45 x^{2} + 87 x + 28

f (x, y) = x^{3} y + x y^{3} - 2 x y

f (x, y) = 3 x^{2} - 3 y^{2} + 2

f (x) = \frac{- 6}{x ^{2} - 9}