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Popular >

extreme f(x)=x^2-8x+4

Solution

extreme points

f (x) = x^{2} - 8 x + 4

Solution

Minimum (4, - 12)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 4 : - 12

Minimum (4, - 12)

Popular Examples

extreme f(x)=e^{x^2-5x-1}extreme points

f (x) = e^{x^{2} - 5 x - 1}

extreme f(x)=2x^3-3x^2-12x+3 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 3

extreme f(x)=(x^2-1)(x-3)extreme points

f (x) = (x^{2} - 1) (x - 3)

extreme f(x)=3x^4 extreme points

f (x) = 3 x^{4}

extreme f(x,y)=x^3+3y^3+3x^2+3y^2+24 extreme points

f (x, y) = x^{3} + 3 y^{3} + 3 x^{2} + 3 y^{2} + 24

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+4 ?
The extreme f(x)=x^2-8x+4 is Minimum(4,-12)