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Popular >

extreme f(x)=(2x)/(x^2-9)

Solution

extreme points

f (x) = \frac{2 x}{x ^{2} - 9}

Solution

None

Solution steps

f^{'} (x) = \frac{2 ( - x ^{2} - 9 )}{( x ^{2} - 9 ) ^{2}}

Find intervals:

None

None

Popular Examples

extreme f(x,y)=y^3+3x^2y-6x^2-6y^2+2 extreme points

f (x, y) = y^{3} + 3 x^{2} y - 6 x^{2} - 6 y^{2} + 2

extreme f(x,y)=4xy-x^4-2y^2 extreme points

f (x, y) = 4 x y - x^{4} - 2 y^{2}

extreme f(x,y)=4x^2+2y^2-2xy-10y-2x extreme points

f (x, y) = 4 x^{2} + 2 y^{2} - 2 x y - 10 y - 2 x

extreme (x-y)(9-xy)extreme points

(x - y) (9 - x y)

extreme f(x)=15x^4+8x^3-18x^2+1 extreme points

f (x) = 15 x^{4} + 8 x^{3} - 18 x^{2} + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(2x)/(x^2-9) ?
The extreme f(x)=(2x)/(x^2-9) is None