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Popular >

extreme (x-5)/(x^2)

Solution

extreme points

\frac{x - 5}{x ^{2}}

Solution

Maximum (10, \frac{1}{20})

Solution steps

f^{'} (x) = \frac{- x + 10}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 10,

Decreasing

: 10 < x < \infty

Plug

x = 10

into

\frac{x - 5}{x ^{2}} : \frac{1}{20}

Maximum (10, \frac{1}{20})

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f (x) = \frac{x ^{2}}{x ^{2} - 5}

extreme f(x,y)=xy-2x-2y-x^2-y^2 extreme points

f (x, y) = x y - 2 x - 2 y - x^{2} - y^{2}

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f (x) = x^{2} \cdot e^{- x}

extreme y=x^2-4x extreme points

y = x^{2} - 4 x

Frequently Asked Questions (FAQ)

What is the extreme (x-5)/(x^2) ?
The extreme (x-5)/(x^2) is Maximum(10, 1/20)