What is the extreme f(x)=x^3-3x^2-9x+7 ?

The extreme f(x)=x^3-3x^2-9x+7 is Maximum(-1,12),Minimum(3,-20)

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extreme f(x)=x^3-3x^2-9x+7

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 7

Maximum (- 1, 12), Minimum (3, - 20)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 7 : 12

Maximum (- 1, 12)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 7 : - 20

Minimum (3, - 20)

Maximum (- 1, 12), Minimum (3, - 20)

f (x) = x^{3} - 3 x^{2} - 9 x + 4

\frac{x}{ln ( x )}

f (x) = x^{3} - 3 x y - y^{2}

f (x) = x^{2} - 4 x + 2

x^{2} - 4 x + 5

What is the extreme f(x)=x^3-3x^2-9x+7 ?
The extreme f(x)=x^3-3x^2-9x+7 is Maximum(-1,12),Minimum(3,-20)