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Popular >

range of 10x^2-15x+2

Solution

range

10 x^{2} - 15 x + 2

Solution

f (x) \geq - \frac{29}{8}

+1

Interval Notation

[- \frac{29}{8}, \infty)

Solution steps

Vertex of

10 x^{2} - 15 x + 2 :

Minimum

(\frac{3}{4}, - \frac{29}{8})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 10,

Vertex

(x_{v}, y_{v}) = (\frac{3}{4}, - \frac{29}{8})

f (x) \geq - \frac{29}{8}

Popular Examples

asymptotes of f(x)=sec(x-pi/2)+4 asymptotes

f (x) = sec (x - \frac{π}{2}) + 4

inverse of f(x)=2x^4-5 inverse

f (x) = 2 x^{4} - 5

inverse of e^{(x^2-4)}-1 inverse

e^{(x^{2} - 4)} - 1

slope ofintercept 4x-3y=-6 slope intercept

4 x - 3 y = - 6

inverse of f(x)=(12)/(x-1)inverse

f (x) = \frac{12}{x - 1}

Frequently Asked Questions (FAQ)

What is the range of 10x^2-15x+2 ?
The range of 10x^2-15x+2 is f(x)>=-29/8