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Popular >

extreme f(x)=x+ln(x^2-3)

Solution

extreme points

f (x) = x + ln (x^{2} - 3)

Solution

Maximum (- 3, - 3 + ln (6))

Solution steps

f^{'} (x) = 1 + \frac{2 x}{x ^{2} - 3}

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < - 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x + ln (x^{2} - 3) : - 3 + ln (6)

Maximum (- 3, - 3 + ln (6))

Popular Examples

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f (x y) = 2 x^{2} - 8 x + y^{2} + 16 y + 100

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g (x) = 2 x^{3} + 3 x^{2} + 12 x - 4

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f (x) = x^{3} - 10 x^{2} + 33 x - 36

extreme x^x extreme points

x^{x}

extreme x^4-6x^3 extreme points

x^{4} - 6 x^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x+ln(x^2-3) ?
The extreme f(x)=x+ln(x^2-3) is Maximum(-3,-3+ln(6))