en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(x+2)^3

Solution

extreme points

f (x) = (x + 2)^{3}

Solution

Saddle (- 2, 0)

Solution steps

f^{'} (x) = 3 (x + 2)^{2}

Find intervals:

Increasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

(x + 2)^{3} : 0

Saddle (- 2, 0)

Popular Examples

extreme f(x)=(4x)/(x^2-36)extreme points

f (x) = \frac{4 x}{x ^{2} - 36}

extreme f(x,y)=1-e^{-x-y}extreme points

f (x, y) = 1 - e^{- x - y}

extreme 3x^4-4x^3-12x^2 extreme points

3 x^{4} - 4 x^{3} - 12 x^{2}

extreme f(x)=(2x^3)/3+3x^2-20x extreme points

f (x) = \frac{2 x ^{3}}{3} + 3 x^{2} - 20 x

extreme f(x)=(x-2)/(x^2)extreme points

f (x) = \frac{x - 2}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x+2)^3 ?
The extreme f(x)=(x+2)^3 is Saddle(-2,0)