What is the extreme f(x)=3-x,-1<= x<= 2 ?

The extreme f(x)=3-x,-1<= x<= 2 is Maximum(-1,4),Minimum(2,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3-x,-1<= x<= 2

extreme points

f (x) = 3 - x, - 1 \leq x \leq 2

Maximum (- 1, 4), Minimum (2, 1)

Solution steps

Find the critical points:

x = - 1, x = 2

Domain of

3 - x, - 1 \leq x \leq 2 : - 1 \leq x \leq 2

Find intervals:

Decreasing

: - 1 < x < 2

Plug the extreme point

x = - 1

into

3 - x \Rightarrow y = 4

Maximum (- 1, 4)

Plug the extreme point

x = 2

into

3 - x \Rightarrow y = 1

Minimum (2, 1)

Maximum (- 1, 4), Minimum (2, 1)

f (x) = x + 2 cos (x)

\frac{x ^{2}}{x + 1}

(x^{3} - 1)^{\frac{2}{3}}

f (x) = 9 y - 18 - 5 x

f (x) = \frac{x}{x ^{2} - x + 25}

What is the extreme f(x)=3-x,-1<= x<= 2 ?
The extreme f(x)=3-x,-1<= x<= 2 is Maximum(-1,4),Minimum(2,1)