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Popular >

extreme f(x)=3y^2+8y

Solution

extreme points

f (x) = 3 y^{2} + 8 y

Solution

Minimum (- \frac{4}{3}, - \frac{16}{3})

Solution steps

f^{'} (y) = 6 y + 8

Find intervals:

Decreasing

: - \infty < y < - \frac{4}{3},

Increasing

: - \frac{4}{3} < y < \infty

Plug

y = - \frac{4}{3}

into

3 y^{2} + 8 y : - \frac{16}{3}

Minimum (- \frac{4}{3}, - \frac{16}{3})

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extreme 2x^2-8x+9 extreme points

2 x^{2} - 8 x + 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=3y^2+8y ?
The extreme f(x)=3y^2+8y is Minimum(-4/3 ,-16/3)