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Popular >

extreme 2x^2-8x+9

Solution

extreme points

2 x^{2} - 8 x + 9

Solution

Minimum (2, 1)

Solution steps

f^{'} (x) = 4 x - 8

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

2 x^{2} - 8 x + 9 : 1

Minimum (2, 1)

Popular Examples

extreme f(x,y)=2-x^4+2x^2-y^2 extreme points

f (x, y) = 2 - x^{4} + 2 x^{2} - y^{2}

extreme f(x)=12x^{2/3}-8x extreme points

f (x) = 12 x^{\frac{2}{3}} - 8 x

extreme f(x)=4x^3-2x^2+x-1 extreme points

f (x) = 4 x^{3} - 2 x^{2} + x - 1

extreme f(x)=x^5-5x^4+8 extreme points

f (x) = x^{5} - 5 x^{4} + 8

extreme f(x)=(6x)/(x^2-49)extreme points

f (x) = \frac{6 x}{x ^{2} - 49}

Frequently Asked Questions (FAQ)

What is the extreme 2x^2-8x+9 ?
The extreme 2x^2-8x+9 is Minimum(2,1)