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Popular >

extreme f(x)=(x^2)/(x^2+4)

Solution

extreme points

f (x) = \frac{x ^{2}}{x ^{2} + 4}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{8 x}{( x ^{2} + 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} + 4} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)=x^{1/3}+2x^{4/3}extreme points

f (x) = x^{\frac{1}{3}} + 2 x^{\frac{4}{3}}

extreme f(x)=x^3-2x^2+4 extreme points

f (x) = x^{3} - 2 x^{2} + 4

extreme f(x)=(4x)/(x^2+9),-4<= x<= 4 extreme points

f (x) = \frac{4 x}{x ^{2} + 9}, - 4 \leq x \leq 4

extreme-3(x+5)^3 extreme points

- 3 (x + 5)^{3}

extreme f(x)=x^3-6x^2+9x+8 extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2)/(x^2+4) ?
The extreme f(x)=(x^2)/(x^2+4) is Minimum(0,0)