What is the extreme f(x,y)=5e^{7xy} ?

The extreme f(x,y)=5e^{7xy} is Saddle(0,0)

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extreme f(x,y)=5e^{7xy}

extreme points

f (x, y) = 5 e^{7 x y}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 245 e^{7 x y} x^{2}

D (x, y) = - 17150 e^{14 x y} x y - 1225 e^{14 x y}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 8 ln (x) - x^{2}

f (t) = u (t)

f (x) = 3 x^{4} + 4 x^{3} - 36 x^{2} - 78

f (x, y) = x^{2} + x y

\frac{D}{D x}

What is the extreme f(x,y)=5e^{7xy} ?
The extreme f(x,y)=5e^{7xy} is Saddle(0,0)