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Popular >

extreme f(x)=x^2-4x+4

Solution

extreme points

f (x) = x^{2} - 4 x + 4

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = 2 x - 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{2} - 4 x + 4 : 0

Minimum (2, 0)

Popular Examples

extreme f(x)=x^4-8x^2+1 extreme points

f (x) = x^{4} - 8 x^{2} + 1

extreme f(x)=x^4-8x^2+6 extreme points

f (x) = x^{4} - 8 x^{2} + 6

extreme f(x,y)=4x^2+y^2-8x+6y+8 extreme points

f (x, y) = 4 x^{2} + y^{2} - 8 x + 6 y + 8

extreme f(x)=ln(27+8x^3)extreme points

f (x) = ln (27 + 8 x^{3})

extreme f(x)=x^5+10x^4+25x^3 extreme points

f (x) = x^{5} + 10 x^{4} + 25 x^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-4x+4 ?
The extreme f(x)=x^2-4x+4 is Minimum(2,0)